y^2+3x+5/y-1=y-2

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Solution for y^2+3x+5/y-1=y-2 equation: 


x in (-oo:+oo)

3*x+y^2+5/y-1 = y-2 // - y-2

3*x+y^2-y+5/y-1+2 = 0

3*x+y^2-y+5*y^-1+1 = 0 // - y^2-y+5*y^-1+1

3*x = -(y^2-y+5*y^-1+1) // : 3

x = (-(y^2-y+5*y^-1+1))/3

x = (-(y^2-y+5*y^-1+1))/3

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